Download e-book for iPad: From Calculus to Analysis by Steen Pedersen

By Steen Pedersen

ISBN-10: 3319136402

ISBN-13: 9783319136400

ISBN-10: 3319136410

ISBN-13: 9783319136417

Routines embedded within the textual content with options on the finish of every section
Approaches the genuine numbers via endless decimals
Classroom demonstrated with either arithmetic and arithmetic schooling majors

This textbook beneficial properties functions together with an explanation of the basic Theorem of Algebra, area filling curves, and the idea of irrational numbers. as well as the normal result of complex calculus, the booklet includes numerous attention-grabbing purposes of those results.

The textual content is meant to shape a bridge among calculus and research. it truly is in keeping with the authors lecture notes used and revised approximately each year during the last decade. The ebook includes a number of illustrations and move references all through, in addition to workouts with options on the finish of every section

Content point » higher undergraduate

Keywords » Derivatives - Fourier sequence - quantity concept - actual Variables - Set Theory

Related topics » Algebra - research

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Additional info for From Calculus to Analysis

Example text

Q(x) q(a) Actually, this requires that a is an accumulation point of {x ∈ C | q(x) = 0}. 11. If p is a polynomial of degree n, then p has at most n roots. This is part of the Fundamental Theorem of Algebra. The full version of the Fundamental Theorem of Algebra is established in Sect. 4. We precede the proof by two lemmas. The idea of the proof of the first lemma is used at several points in the text. 12. If p is a polynomial of degree n and z0 is a constant, then q(z) := p(z + z0 ) is a polynomial of degree n.

On the other hand, if m < ε , then D ∩ Bε (c) ⊇ D ∩ Bm (c) and the right hand side is nonempty by assumption. 9. If |x − 1/2| < 1/4, then −1/4 < x − 1/2 < 1/4, and therefore 1/4 < x < 3/4. But 1/4 < x, implies 0 < 2/x < 8. Hence, x− 2 1 1 1 1 < =⇒ x− < 8 x− . 2 4 x 2 2 Consequently, if |x − 1/2| < 1/4 and |x − 1/2| < ε /8, then ε 2 1 1 x − < 8 x − < 8 = ε. x 2 2 8 Thus, δ := min{1/4, ε /8} works. 11. (i). It is easy to justify: g ({x | 0 < |x − 0| < δ }) ⊇ {g(x) | 0 < x < δ } = {σ (1/x) | 0 < x < δ } = {σ (t) | 1/δ < t} ⊇ {−1, 1}.

4. If f : R → C is continuous on R and f (x) = x2 for every rational x, show f (x) = x2 for every real x. 5. If f : R → R is continuous and f (x + y) = f (x) + f (y) for all x, y ∈ R, then there is constant c ∈ R, such that f (x) = cx, for all x in R. [Hint: f (2) = f (1 + 1) = 2 f (1), and f (1) = f (1/2) + f (1/2) = 2 f (1/2), so f (1/2) = 12 f (1)]. 6. Let f : C → C be continuous at a. Suppose (xn ) is a sequence of complex numbers converging to a. Prove the sequence ( f (xn )) converges to f (a).

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From Calculus to Analysis by Steen Pedersen

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